Math/design question

I am doing multiple cables within a row. There is a c4 that repeats alternately every 4 or 6 rows and a twisted 6 st cable that repeats every 6 rows.

How many rows do I have to chart until the whole set of cables repeats? I was thinking 60 but that seemed like too many

The mathematics of this

The mathematics of this repeat problem is that you multiply the two numbers, and that will give you a point where they will repeat again. So 4 x 6 is 24. But half of that may work as well.... so 12. The cable crossing every 4 rows will have three crossings in 12 rows.... the cable crossing every 6 rows will have two crossings in 12 rows. And the cables that crossed at the same time on row 1 will again cross at the same time on row 12 and every 12 rows thereafter. As Mr. Ross said, 12 is the lowest number divisible by both 6 and 4.

Which would be correct IF the

Which would be correct IF the cables were a four and a six row cable

but actually they are a 10 row and a six row cable.

One cable alternates between 4 and six rows; one repeat is 10 rows. three repeats is 30 rows.

the second cable is a six row cable. five repeats is 30 rows.

Mmario I believe has it right

Mmario I believe has it right and it makes sense. Thanks all

Yes, I believe it repeats

Yes, I believe it repeats every 30 as well. 6 * 5 = 30, 10 * 3 = 30.

Unless I'm misunderstanding

Unless I'm misunderstanding your question, with a 4 row repeat and a 6 row repeat, I think a 12 row chart would incorporate the various cable repeats. (i.e. 12 is the lowest number that can be divided evenly by 4 and 6).

I was not clear. I have side

I was not clear. I have side by side different cables. One is c4 which alternates between every fourth and every sixth row. That makes it's repeat every 10 rows. The other is every 6 rows of twisted cable. The first peat is at 30, the first combo of six rows that is divisible by 10.

Thanks

the pattern repeats every

the pattern repeats every thirty rows.